(2x^2-5x-12)/(2x^-4x-16)

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Solution for (2x^2-5x-12)/(2x^-4x-16) equation:


D( x )

x = 0

2*x^-4*x-16 = 0

x = 0

x = 0

2*x^-4*x-16 = 0

2*x^-4*x-16 = 0

2*x^-3 = 16 // : 2

x^-3 = 8

-3 < 0

1/(x^3) = 8 // * x^3

1 = 8*x^3 // : 8

1/8 = x^3

x^3 = 1/8 // ^ 1/3

x = 1/2

x in (-oo:0) U (0:1/2) U (1/2:+oo)

(2*x^2-(5*x)-12)/(2*x^-4*x-16) = 0

(2*x^2-5*x-12)/(2*x^-4*x-16) = 0

(2*x^2-5*x-12)/(2*x^-3-16) = 0

2*x^2-5*x-12 = 0

2*x^2-5*x-12 = 0

DELTA = (-5)^2-(-12*2*4)

DELTA = 121

DELTA > 0

x = (121^(1/2)+5)/(2*2) or x = (5-121^(1/2))/(2*2)

x = 4 or x = -3/2

(x+3/2)*(x-4) = 0

((x+3/2)*(x-4))/(2*x^-3-16) = 0

( x+3/2 )

x+3/2 = 0 // - 3/2

x = -3/2

( x-4 )

x-4 = 0 // + 4

x = 4

x in { -3/2, 4 }

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